Broad use base and number of users both in industry and academia

Friendly, prompt and professional support

Continuously developed in cooperation with leading institutes


Home Forums Asimptote knowledge forum Calculation of specific heat capacities

Viewing 4 reply threads
  • Author
    • #1715

      Is there any way we can find the specific heat (kJ/kg-K) of a fluid using Cycle-Tempo? I checked in View—>Text Output but did not find.

    • #1716

      Dear Turbouser, unfortunately, there isn’t. You can only use FluidProp, e.g. in Excel, and the HeatCapP function to retrieve cp of a fluid.

    • #1719

      Attached you can find a screenshot that shows how you can calculate specific heat capacities with FluidProp in Excel.

      You must be logged in to view attached files.
    • #1767

      Of course it is possible to calculate cp = delta(h) / (delta(T)
      This way it is possible to calaulate the mean cp for the required trajectory. It is not given in the Cycle-Tempo-output, but it is easy to calculate from the enthalpies and temperatures given in the output of Cycle-Tempo.

    • #1768

      Dear Professor, this method is applicable when a process/reaction is taking place. Suppose, I have a gas mixture and it is not undergoing any process like in the schematic shown below. Cycle-Tempo will give the enthalpy but how to compute Cp? In this case, we cant use Cp=dH/dT.
      For air, we know that Cp=1.005 kJ/kg-K at room temperature. How to obtain this value using Cycle-Tempo, without giving a slight rise in temperature?

      • #1770

        However, I think there is no harm in carrying out this little exercise of giving a small rise in temperature to compute the Cp using dH/dT

Viewing 4 reply threads
  • You must be logged in to reply to this topic.